Given an array consists of non-negative integers, your task is to count the number of triplets chosen from the array that can make triangles if we take them as side lengths of a triangle.
Example
1 2 3 4 5 6 7
Input: [2,2,3,4] Output: 3 Explanation: Valid combinations are: 2,3,4 (using the first 2) 2,3,4 (using the second 2) 2,2,3
Note:
The length of the given array won’t exceed 1000.
The integers in the given array are in the range of [0, 1000].
classSolution{ publicinttriangleNumber(int[] nums){ if (nums == null || nums.length == 0) return0; Arrays.sort(nums); int res = 0; for (int i = 2; i < nums.length; i++){ int left = 0; int right = i - 1; while(left < right){ if (nums[left] + nums[right] > nums[i]){ res += right - left; right--; } else left++; } } return res; } }