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Leetcode199-binaryTreeRightSideView

Description

Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.

Example

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Input: [1,2,3,null,5,null,4]
Output: [1, 3, 4]
Explanation:

1 <---
/ \
2 3 <---
\ \
5 4 <---

Solution

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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<Integer> rightSideView(TreeNode root) {
List<Integer> res = new ArrayList<>();
if (root == null) return res;

Queue<TreeNode> q = new LinkedList<>();
q.offer(root);
while(!q.isEmpty()){
int size = q.size();
for (int i = 0; i < size; i++){
TreeNode node = q.poll();
if (node.left != null) q.offer(node.left);
if (node.right != null) q.offer(node.right);
if (i == size - 1) res.add(node.val);
}
}
return res;
}
}