Description
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array
Note:
- The number of elements initialized in nums1 and nums2 are m and n respectively.
- You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Example
1 | Input: |
Solution
Solution: best solution1
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18class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int i = m - 1;
int j = n - 1;
int k = m + n -1;
while (i >= 0 && j >= 0){
if (nums1[i] > nums2[j]){
nums1[k--] = nums1[i--];
}
else
nums1[k--] = nums2[j--];
}
while (i >= 0)
nums1[k--] = nums1[i--];
while (j >= 0)
nums1[k--] = nums2[j--];
}
}
Solution 2: Not a good solution1
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23class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
if (n == 0) return;
int[] tmp = new int[n + m];
int i = 0;
int j = 0;
int index = 0;
while (i < m && j < n){
if (nums1[i] <= nums2[j]){
tmp[index++] = nums1[i++];
}
else{
tmp[index++] = nums2[j++];
}
}
if (i < m)
for (int k = i; i < m; k++) tmp[index++] = nums1[i++];
if (j < n)
for (int k = j; j < n; k++) tmp[index++] = nums2[j++];
for (int k = 0; k < m + n; k++)
nums1[k] = tmp[k];
}
}