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Leetcode035-searchInsertPosition

Description

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Example

Example 1:

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Input: [1,3,5,6], 5
Output: 2

Example 2:
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Input: [1,3,5,6], 2
Output: 1

Example 3:
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Input: [1,3,5,6], 7
Output: 4

Example 4:
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Input: [1,3,5,6], 0
Output: 0

Solution

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class Solution {
public int searchInsert(int[] nums, int target) {
if (nums == null || nums.length == 0) return 0;

// O(logn) Method, Binary Search
if (target > nums[nums.length - 1]) return nums.length;
int left = 0;
int right = nums.length - 1;
while(left < right){
int mid = left + (right - left)/2;
if (nums[mid] == target) return mid;
else if (nums[mid] < target) left = mid + 1;
else right = mid;
}
return left;

// O(n) Method
// for (int i = 0; i < nums.length; i++){
// if (target <= nums[i]) return i;
// }
// return nums.length;
}
}