Leetcode713-subarrayProductLessThanK

Description

Your are given an array of positive integers nums.

Count and print the number of (contiguous) subarrays where the product of all the elements in the subarray is less than k.

Example

Input: nums = [10, 5, 2, 6], k = 100
Output: 8
Explanation: The 8 subarrays that have product less than 100 are: [10], [5], [2], [6], [10, 5], [5, 2], [2, 6], [5, 2, 6].
Note that [10, 5, 2] is not included as the product of 100 is not strictly less than k.

Note:

• 0 < nums.length <= 50000.
• 0 < nums[i] < 1000.
• 0 <= k < 10^6.

Solution

class Solution {
    public int numSubarrayProductLessThanK(int[] nums, int k) {
        if (k == 0) return 0;
        int res = 0;
        int i = 0;
        int j = 0;
        int product = 1;
        while(j < nums.length){
            product *= nums[j];
            while(i <= j && product >= k){
                product /= nums[i];
                i++;
            }
            res += j - i + 1;
            j++;
        }
        return res;
    }
}

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