Description
A string S of lowercase letters is given. We want to partition this string into as many parts as possible so that each letter appears in at most one part, and return a list of integers representing the size of these parts.
Example
1 | Input: S = "ababcbacadefegdehijhklij" |
Note:
- S will have length in range [1, 500].
- S will consist of lowercase letters (‘a’ to ‘z’) only.
Solution
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23class Solution {
public List<Integer> partitionLabels(String S) {
List<Integer> res = new ArrayList<>();
if (S == null || S.length() == 0) return res;
int[] index = new int[26];
for (int i = 0; i < S.length(); i++){
index[S.charAt(i) - 'a'] = i;
}
int start = 0;
int end = 0;
for (int i = 0; i < S.length(); i++){
end = Math.max(end, index[S.charAt(i) - 'a']);
if (end == i){
res.add(end - start + 1);
start = end + 1;
}
}
return res;
}
}