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Leetcode341-flattenNestedListIterator

Description

Given a nested list of integers, implement an iterator to flatten it.

Each element is either an integer, or a list — whose elements may also be integers or other lists.

Example

Example 1:

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Input: [[1,1],2,[1,1]]
Output: [1,1,2,1,1]
Explanation: By calling next repeatedly until hasNext returns false,
the order of elements returned by next should be: [1,1,2,1,1].

Example 2:
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Input: [1,[4,[6]]]
Output: [1,4,6]
Explanation: By calling next repeatedly until hasNext returns false,
the order of elements returned by next should be: [1,4,6].

Solution

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/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class NestedIterator implements Iterator<Integer> {

LinkedList<Integer> q;

public NestedIterator(List<NestedInteger> nestedList) {
q = new LinkedList<>();
helper(nestedList);
}

private void helper(List<NestedInteger> list){
if (list == null) return;

for (NestedInteger it: list){
if (it.isInteger()) q.offer(it.getInteger());
else helper(it.getList());
}
}

@Override
public Integer next() {
if (hasNext()) return q.poll();
else return null;
}

@Override
public boolean hasNext() {
if (!q.isEmpty()) return true;
return false;
}
}

/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i = new NestedIterator(nestedList);
* while (i.hasNext()) v[f()] = i.next();
*/