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Dijstra and Floyd

Implementation

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def dijstra(s):
global n
global cost
len = [1000 for i in range(n)]
visit = [0 for i in range(n)]

for i in range(n):
len[i] = cost[s][i]
visit[i] = 0
visit[s] = 1

for i in range(n-1):
min = 10000
for j in range(n):
if (visit[j]==0 and min>len[j]):
min = len[j]
pos = j

visit[pos] = 1

for j in range(n):
if (visit[j] == 0 and len[j]>len[pos] + cost[pos][j]):
len[j] = len[pos] + cost[pos][j]

print(len)



def floyd():
global n
global cost
path = [[0 for i in range(n)]for j in range(n)]
length = [[0 for i in range(n)]for j in range(n)]
for i in range(n):
for j in range(n):
length[i][j] = cost[i][j]
if cost[i][j] < 1000:
path[i][j] = i
else:
path[i][j] = -1

for k in range(n):
for i in range(n):
for j in range(n):
if (length[i][k] < 1000)and (length[k][j] < 1000):
if (length[i][j] > length[i][k] + length[k][j]):
length[i][j] = length[i][k] + length[k][j]
path[i][j] = k

for i in range(n):
print(length[i])

global n
n = int(input('Please input the number of notes: '))
cost = []
for i in range(n):
cost.append(list(map(int, input().split(' '))))

s = int(input('Please input the source: '))
dijstra(s)


input('Please run floyd')
floyd()